With Clusters Posted May 18, 2004 Share Posted May 18, 2004 I don't get it either - feel like I'm back in some horrible math/science class I just figure that the bigger number after the 'L/' the better, at least when it comes to shooting at tanks. Seems to work OK 0 Quote Link to comment Share on other sites More sharing options...
Sergei Posted May 18, 2004 Share Posted May 18, 2004 In both cases the original charge is the same - 5 "arrows". But because the below gun barrel is shorter, part of the energy is not delivered to the shot. Thus a lower muzzle velocity. Thus a bigger charge requires a longer barrel to take effect. A bigger shot requires even bigger charge because it is heavier. Let's say twice heavier, thus requiring twice as big explosive charge. For that charge you need twice as long a barrel to burn so that the twice bigger shot has the same MV as the small shot. While twice longer in absolute terms, they have the same caliber length. Maybe this is simplified, but I'm a simple guy. 0 Quote Link to comment Share on other sites More sharing options...
flamingknives Posted May 18, 2004 Share Posted May 18, 2004 Of course, it can get complicated by some guns have a larger charge. Hence the 75L46 is a more powerful weapon than the 75L48. Sergei: Being as weight (mass) is a function of volume (distance cubed), assuming the material is the same, a shell twice as heavy isn't going to be twice as wide. 0 Quote Link to comment Share on other sites More sharing options...
Sergei Posted May 18, 2004 Share Posted May 18, 2004 Well yeah, but... I'm a simple guyIt's the principle I was looking for. 0 Quote Link to comment Share on other sites More sharing options...
Other Means Posted May 18, 2004 Share Posted May 18, 2004 thanks. i had got there myself. but why not 40/L46.5 etc? 0 Quote Link to comment Share on other sites More sharing options...
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