Claymore Posted August 8, 2002 Share Posted August 8, 2002 How does CMBO model the %kill for a HEAT round as a function of %penetration. A posting to the TANKNET forums by Paul L. peaked my interest. He is the most credible source on penetration calculations on that forum (IMO). I quote (without permisssion)his comments on the Stryker protection against RPGs. "using modern BAD simulations [ used by top NATO armies], a warhead that can just bearly penetrate tanks armor is estiamted to have a kill % of ~ 10%, while the same warhead striking the same target with 1/2 as much armor as the warheads penetration..should result in a kill% of 1/2 to 2/3....in other words in order for a RPG to have a 'good chance' of a kill [50-67%] it would have to have twice as much penetration or 55-60cm.....going on the current BAD simulations" Cheers MRD Link to comment Share on other sites More sharing options...
phancucchin@aol.com Posted August 8, 2002 Share Posted August 8, 2002 Originally posted by Claymore: How does CMBO model the %kill for a HEAT round as a function of %penetration. "using modern BAD simulations [ used by top NATO armies], a warhead that can just bearly penetrate tanks armor is estiamted to have a kill % of ~ 10%, while the same warhead striking the same target with 1/2 as much armor as the warheads penetration..should result in a kill% of 1/2 to 2/3....in other words in order for a RPG to have a 'good chance' of a kill [50-67%] it would have to have twice as much penetration or 55-60cm.....going on the current BAD simulations" Cheers MRDThis is for the modern period armor with internal protections such as halon? Perhaps the WWII gasoline engined tank is more susceptible? Link to comment Share on other sites More sharing options...
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