Diceman Posted January 5, 2001 Share Posted January 5, 2001 I used to know how to do this but it's been 20 years since physics class. Can anyone tell me how to calculate kinetic energy of a round? For instance a 3.7 cm KwK L/46.5 gun has a projectile weight of .685 kg, and a muzzle velocity of 745 m/s. What's it's kinetic energy? Also, what was the weight of the AP shell used by the Sherman L40 gun? Thanks in Advance. Eric ------------------ Pair-O-Dice "Once a Diceman, Always a Diceman." Link to comment Share on other sites More sharing options...
StellarRat Posted January 5, 2001 Share Posted January 5, 2001 K=MV^2 Link to comment Share on other sites More sharing options...
Banshee Posted January 5, 2001 Share Posted January 5, 2001 ke = 1/2 mv^2 Kinetic Energy equals one-half mass times the square of velocity Link to comment Share on other sites More sharing options...
Banshee Posted January 5, 2001 Share Posted January 5, 2001 Doh! Im doing it from memory, but I really thought it had 1/2 in there, u sure stellarRat? ------------------ Veni, vidi, panzerschrecki Link to comment Share on other sites More sharing options...
StellarRat Posted January 5, 2001 Share Posted January 5, 2001 Sorry it is K = 1/2MV^2. Goofed. Of course for comparative purposes the 1/2 doesn't make any difference. Link to comment Share on other sites More sharing options...
Diceman Posted January 5, 2001 Author Share Posted January 5, 2001 So the kinetic energy of the 37 mm gun in question is 190096 km's? While a 50mm L/60 with a 2.06 kg round and muzzle velocity of 835 m/s has a kinetic energy of: 718142 km's? or 3.8 times the kinetic energy right? ------------------ Pair-O-Dice "Once a Diceman, Always a Diceman." Link to comment Share on other sites More sharing options...
Banshee Posted January 5, 2001 Share Posted January 5, 2001 I am pretty sure KG M^2/S^2 is some sort of unit (Joules or newtons), but I always forget such things. but for compartive purposes it dont matter Edit: It's Joules. ------------------ Veni, vidi, panzerschrecki [This message has been edited by Banshee (edited 01-04-2001).] Link to comment Share on other sites More sharing options...
Diceman Posted January 5, 2001 Author Share Posted January 5, 2001 Thanks guys, I was trying to compare the gun power of a PZIII E to a PZIII L. You've been a great help. Chears Eric ------------------ Pair-O-Dice "Once a Diceman, Always a Diceman." Link to comment Share on other sites More sharing options...
StellarRat Posted January 5, 2001 Share Posted January 5, 2001 <BLOCKQUOTE>quote:</font><HR>Originally posted by Diceman: So the kinetic energy of the 37 mm gun in question is 190096 km's? While a 50mm L/60 with a 2.06 kg round and muzzle velocity of 835 m/s has a kinetic energy of: 718142 km's? or 3.8 times the kinetic energy right? <HR></BLOCKQUOTE> I think you're on the right track. Of course you need to take into account air friction, range, projectile shape and hardness, angle of incidence to the target, etc... to really start nailing down a problem like this. Link to comment Share on other sites More sharing options...
Olle Petersson Posted January 11, 2001 Share Posted January 11, 2001 <BLOCKQUOTE>quote:</font><HR>Originally posted by Banshee: I am pretty sure KG M^2/S^2 is some sort of unit (Joules or newtons), ... Edit: It's Joules.<HR></BLOCKQUOTE>Using the SI system; Energy (W, energy in general, or K, kinetic energy) is in joules (J) = 1 kgm^2/s^2. Mass (m) is in kilogram (kg) (basic unit). Velocity (v) is in metres per second (m/s). Please note that there's a huge difference between capital letters and lower case letters. Joule is the name of a person, joule is a unit of energy. Cheers Olle ------------------ Srategy is the art of avoiding a fair fight... Link to comment Share on other sites More sharing options...
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